F(2)=3x^2-4x+7

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Solution for F(2)=3x^2-4x+7 equation: 



(2)=3F^2-4F+7

We move all terms to the left:

(2)-(3F^2-4F+7)=0

We get rid of parentheses

-3F^2+4F-7+2=0

We add all the numbers together, and all the variables

-3F^2+4F-5=0

a = -3; b = 4; c = -5;
Δ = b2-4ac
Δ = 42-4·(-3)·(-5)
Δ = -44
Delta is less than zero, so there is no solution for the equation

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